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Solve 8x + 6 = āˆ’42

The solution of 8x + 6 = āˆ’42 is x = -6.

The lines y = 8x + 6 and y = -42 meet at x = -6-12-10-8-6-4-2-80-60-40-20x = -6y = 8x + 6y = -42
The lines y = 8x + 6 and y = -42 meet at x = -6. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    8x+6=āˆ’428x + 6 = -42
  2. 2

    Subtract 6 from both sides:

    8x+6āˆ’6=āˆ’42āˆ’6 ⇒ 8x=āˆ’488x + 6 - 6 = -42 - 6 \ \Rightarrow\ 8x = -48
  3. 3

    Divide both sides by 8:

    8x8=āˆ’488 ⇒ x=āˆ’6\frac{8x}{8} = \frac{-48}{8} \ \Rightarrow\ x = -6
  4. 4

    Check: put x = -6 back into the equation.

    8ā‹…(āˆ’6)+6=āˆ’48+6=āˆ’42āœ“8\cdot(-6) + 6 = -48 + 6 = -42 \checkmark
LaTeX source of the formulas on this page
\[ 8x + 6 = -42\ \Rightarrow\ x = -6 \]
\[ 8x + 6 = -42 \]
\[ 8x + 6 - 6 = -42 - 6 \ \Rightarrow\ 8x = -48 \]
\[ \frac{8x}{8} = \frac{-48}{8} \ \Rightarrow\ x = -6 \]
\[ 8\cdot(-6) + 6 = -48 + 6 = -42 \checkmark \]

Trying values of x in 8x + 6 = āˆ’42

x8x + 6Equals -42?
-8-58no
-7-50no
-6-42yes
-5-34no
-4-26no

Questions

What is x in 8x + 6 = āˆ’42?

The solution of 8x + 6 = āˆ’42 is x = -6.

How do you solve 8x + 6 = āˆ’42?

Subtract 6 from both sides to get 8x = -48, then divide both sides by 8 to get x = -6.

How do I check the answer?

Replace x by -6: 8(-6) + 6 = -42, which is -42.

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    Solve 8x + 6 = āˆ’42: x = -6 (steps and check) | WordGPT