Solve 9x + 6 = ā48
The solution of 9x + 6 = ā48 is x = -6.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 6 from both sides:
- 3
Divide both sides by 9:
- 4
Check: put x = -6 back into the equation.
LaTeX source of the formulas on this page
\[ 9x + 6 = -48\ \Rightarrow\ x = -6 \]
\[ 9x + 6 = -48 \]
\[ 9x + 6 - 6 = -48 - 6 \ \Rightarrow\ 9x = -54 \]
\[ \frac{9x}{9} = \frac{-54}{9} \ \Rightarrow\ x = -6 \]
\[ 9\cdot(-6) + 6 = -54 + 6 = -48 \checkmark \]Trying values of x in 9x + 6 = ā48
| x | 9x + 6 | Equals -48? |
|---|---|---|
| -8 | -66 | no |
| -7 | -57 | no |
| -6 | -48 | yes |
| -5 | -39 | no |
| -4 | -30 | no |
Questions
What is x in 9x + 6 = ā48?
The solution of 9x + 6 = ā48 is x = -6.
How do you solve 9x + 6 = ā48?
Subtract 6 from both sides to get 9x = -54, then divide both sides by 9 to get x = -6.
How do I check the answer?
Replace x by -6: 9(-6) + 6 = -48, which is -48.