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Solve 8x + 10 = āˆ’38

The solution of 8x + 10 = āˆ’38 is x = -6.

The lines y = 8x + 10 and y = -38 meet at x = -6-12-10-8-6-4-2-80-60-40-2020x = -6y = 8x + 10y = -38
The lines y = 8x + 10 and y = -38 meet at x = -6. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    8x+10=āˆ’388x + 10 = -38
  2. 2

    Subtract 10 from both sides:

    8x+10āˆ’10=āˆ’38āˆ’10 ⇒ 8x=āˆ’488x + 10 - 10 = -38 - 10 \ \Rightarrow\ 8x = -48
  3. 3

    Divide both sides by 8:

    8x8=āˆ’488 ⇒ x=āˆ’6\frac{8x}{8} = \frac{-48}{8} \ \Rightarrow\ x = -6
  4. 4

    Check: put x = -6 back into the equation.

    8ā‹…(āˆ’6)+10=āˆ’48+10=āˆ’38āœ“8\cdot(-6) + 10 = -48 + 10 = -38 \checkmark
LaTeX source of the formulas on this page
\[ 8x + 10 = -38\ \Rightarrow\ x = -6 \]
\[ 8x + 10 = -38 \]
\[ 8x + 10 - 10 = -38 - 10 \ \Rightarrow\ 8x = -48 \]
\[ \frac{8x}{8} = \frac{-48}{8} \ \Rightarrow\ x = -6 \]
\[ 8\cdot(-6) + 10 = -48 + 10 = -38 \checkmark \]

Trying values of x in 8x + 10 = āˆ’38

x8x + 10Equals -38?
-8-54no
-7-46no
-6-38yes
-5-30no
-4-22no

Questions

What is x in 8x + 10 = āˆ’38?

The solution of 8x + 10 = āˆ’38 is x = -6.

How do you solve 8x + 10 = āˆ’38?

Subtract 10 from both sides to get 8x = -48, then divide both sides by 8 to get x = -6.

How do I check the answer?

Replace x by -6: 8(-6) + 10 = -38, which is -38.

Similar equations

    Solve 8x + 10 = āˆ’38: x = -6 (steps and check) | WordGPT