Solve 8x + 10 = ā38
The solution of 8x + 10 = ā38 is x = -6.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 10 from both sides:
- 3
Divide both sides by 8:
- 4
Check: put x = -6 back into the equation.
LaTeX source of the formulas on this page
\[ 8x + 10 = -38\ \Rightarrow\ x = -6 \]
\[ 8x + 10 = -38 \]
\[ 8x + 10 - 10 = -38 - 10 \ \Rightarrow\ 8x = -48 \]
\[ \frac{8x}{8} = \frac{-48}{8} \ \Rightarrow\ x = -6 \]
\[ 8\cdot(-6) + 10 = -48 + 10 = -38 \checkmark \]Trying values of x in 8x + 10 = ā38
| x | 8x + 10 | Equals -38? |
|---|---|---|
| -8 | -54 | no |
| -7 | -46 | no |
| -6 | -38 | yes |
| -5 | -30 | no |
| -4 | -22 | no |
Questions
What is x in 8x + 10 = ā38?
The solution of 8x + 10 = ā38 is x = -6.
How do you solve 8x + 10 = ā38?
Subtract 10 from both sides to get 8x = -48, then divide both sides by 8 to get x = -6.
How do I check the answer?
Replace x by -6: 8(-6) + 10 = -38, which is -38.