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Solve 8x āˆ’ 10 = āˆ’58

The solution of 8x āˆ’ 10 = āˆ’58 is x = -6.

The lines y = 8x āˆ’ 10 and y = -58 meet at x = -6-12-10-8-6-4-2-100-80-60-40-20x = -6y = 8x āˆ’ 10y = -58
The lines y = 8x āˆ’ 10 and y = -58 meet at x = -6. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    8xāˆ’10=āˆ’588x - 10 = -58
  2. 2

    Add 10 to both sides:

    8xāˆ’10+10=āˆ’58+10 ⇒ 8x=āˆ’488x - 10 + 10 = -58 + 10 \ \Rightarrow\ 8x = -48
  3. 3

    Divide both sides by 8:

    8x8=āˆ’488 ⇒ x=āˆ’6\frac{8x}{8} = \frac{-48}{8} \ \Rightarrow\ x = -6
  4. 4

    Check: put x = -6 back into the equation.

    8ā‹…(āˆ’6)āˆ’10=āˆ’48āˆ’10=āˆ’58āœ“8\cdot(-6) - 10 = -48 - 10 = -58 \checkmark
LaTeX source of the formulas on this page
\[ 8x - 10 = -58\ \Rightarrow\ x = -6 \]
\[ 8x - 10 = -58 \]
\[ 8x - 10 + 10 = -58 + 10 \ \Rightarrow\ 8x = -48 \]
\[ \frac{8x}{8} = \frac{-48}{8} \ \Rightarrow\ x = -6 \]
\[ 8\cdot(-6) - 10 = -48 - 10 = -58 \checkmark \]

Trying values of x in 8x āˆ’ 10 = āˆ’58

x8x āˆ’ 10Equals -58?
-8-74no
-7-66no
-6-58yes
-5-50no
-4-42no

Questions

What is x in 8x āˆ’ 10 = āˆ’58?

The solution of 8x āˆ’ 10 = āˆ’58 is x = -6.

How do you solve 8x āˆ’ 10 = āˆ’58?

Add 10 to both sides to get 8x = -48, then divide both sides by 8 to get x = -6.

How do I check the answer?

Replace x by -6: 8(-6) āˆ’ 10 = -58, which is -58.

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    Solve 8x āˆ’ 10 = āˆ’58: x = -6 (steps and check) | WordGPT