Solve 8x + 10 = ā22
The solution of 8x + 10 = ā22 is x = -4.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 10 from both sides:
- 3
Divide both sides by 8:
- 4
Check: put x = -4 back into the equation.
LaTeX source of the formulas on this page
\[ 8x + 10 = -22\ \Rightarrow\ x = -4 \]
\[ 8x + 10 = -22 \]
\[ 8x + 10 - 10 = -22 - 10 \ \Rightarrow\ 8x = -32 \]
\[ \frac{8x}{8} = \frac{-32}{8} \ \Rightarrow\ x = -4 \]
\[ 8\cdot(-4) + 10 = -32 + 10 = -22 \checkmark \]Trying values of x in 8x + 10 = ā22
| x | 8x + 10 | Equals -22? |
|---|---|---|
| -6 | -38 | no |
| -5 | -30 | no |
| -4 | -22 | yes |
| -3 | -14 | no |
| -2 | -6 | no |
Questions
What is x in 8x + 10 = ā22?
The solution of 8x + 10 = ā22 is x = -4.
How do you solve 8x + 10 = ā22?
Subtract 10 from both sides to get 8x = -32, then divide both sides by 8 to get x = -4.
How do I check the answer?
Replace x by -4: 8(-4) + 10 = -22, which is -22.