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Solve 8x āˆ’ 10 = āˆ’42

The solution of 8x āˆ’ 10 = āˆ’42 is x = -4.

The lines y = 8x āˆ’ 10 and y = -42 meet at x = -4-10-8-6-4-22-80-60-40-20x = -4y = 8x āˆ’ 10y = -42
The lines y = 8x āˆ’ 10 and y = -42 meet at x = -4. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    8xāˆ’10=āˆ’428x - 10 = -42
  2. 2

    Add 10 to both sides:

    8xāˆ’10+10=āˆ’42+10 ⇒ 8x=āˆ’328x - 10 + 10 = -42 + 10 \ \Rightarrow\ 8x = -32
  3. 3

    Divide both sides by 8:

    8x8=āˆ’328 ⇒ x=āˆ’4\frac{8x}{8} = \frac{-32}{8} \ \Rightarrow\ x = -4
  4. 4

    Check: put x = -4 back into the equation.

    8ā‹…(āˆ’4)āˆ’10=āˆ’32āˆ’10=āˆ’42āœ“8\cdot(-4) - 10 = -32 - 10 = -42 \checkmark
LaTeX source of the formulas on this page
\[ 8x - 10 = -42\ \Rightarrow\ x = -4 \]
\[ 8x - 10 = -42 \]
\[ 8x - 10 + 10 = -42 + 10 \ \Rightarrow\ 8x = -32 \]
\[ \frac{8x}{8} = \frac{-32}{8} \ \Rightarrow\ x = -4 \]
\[ 8\cdot(-4) - 10 = -32 - 10 = -42 \checkmark \]

Trying values of x in 8x āˆ’ 10 = āˆ’42

x8x āˆ’ 10Equals -42?
-6-58no
-5-50no
-4-42yes
-3-34no
-2-26no

Questions

What is x in 8x āˆ’ 10 = āˆ’42?

The solution of 8x āˆ’ 10 = āˆ’42 is x = -4.

How do you solve 8x āˆ’ 10 = āˆ’42?

Add 10 to both sides to get 8x = -32, then divide both sides by 8 to get x = -4.

How do I check the answer?

Replace x by -4: 8(-4) āˆ’ 10 = -42, which is -42.

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    Solve 8x āˆ’ 10 = āˆ’42: x = -4 (steps and check) | WordGPT