Solve 8x + 1 = 65
The solution of 8x + 1 = 65 is x = 8.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 1 from both sides:
- 3
Divide both sides by 8:
- 4
Check: put x = 8 back into the equation.
LaTeX source of the formulas on this page
\[ 8x + 1 = 65\ \Rightarrow\ x = 8 \]
\[ 8x + 1 = 65 \]
\[ 8x + 1 - 1 = 65 - 1 \ \Rightarrow\ 8x = 64 \]
\[ \frac{8x}{8} = \frac{64}{8} \ \Rightarrow\ x = 8 \]
\[ 8\cdot8 + 1 = 64 + 1 = 65 \checkmark \]Trying values of x in 8x + 1 = 65
| x | 8x + 1 | Equals 65? |
|---|---|---|
| 6 | 49 | no |
| 7 | 57 | no |
| 8 | 65 | yes |
| 9 | 73 | no |
| 10 | 81 | no |
Questions
What is x in 8x + 1 = 65?
The solution of 8x + 1 = 65 is x = 8.
How do you solve 8x + 1 = 65?
Subtract 1 from both sides to get 8x = 64, then divide both sides by 8 to get x = 8.
How do I check the answer?
Replace x by 8: 8(8) + 1 = 65, which is 65.