Solve 8x − 1 = 63

The solution of 8x − 1 = 63 is x = 8.

8x - 1 = 63\ \Rightarrow\ x = 8

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The lines y = 8x − 1 and y = 63 meet at x = 8. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

1
The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.
$8x - 1 = 63$
2
Add 1 to both sides:
$8x - 1 + 1 = 63 + 1 \ \Rightarrow\ 8x = 64$
3
Divide both sides by 8:
$\frac{8x}{8} = \frac{64}{8} \ \Rightarrow\ x = 8$
4
Check: put x = 8 back into the equation.
$8\cdot8 - 1 = 64 - 1 = 63 \checkmark$

LaTeX source of the formulas on this page

\[ 8x - 1 = 63\ \Rightarrow\ x = 8 \]
\[ 8x - 1 = 63 \]
\[ 8x - 1 + 1 = 63 + 1 \ \Rightarrow\ 8x = 64 \]
\[ \frac{8x}{8} = \frac{64}{8} \ \Rightarrow\ x = 8 \]
\[ 8\cdot8 - 1 = 64 - 1 = 63 \checkmark \]

Trying values of x in 8x − 1 = 63

x	8x − 1	Equals 63?
6	47	no
7	55	no
8	63	yes
9	71	no
10	79	no

Questions

What is x in 8x − 1 = 63?

The solution of 8x − 1 = 63 is x = 8.

How do you solve 8x − 1 = 63?

Add 1 to both sides to get 8x = 64, then divide both sides by 8 to get x = 8.

How do I check the answer?

Replace x by 8: 8(8) − 1 = 63, which is 63.

Solve 8x − 1 = 63

How to work it out

Trying values of x in 8x − 1 = 63

Questions

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