Solve 8x + 1 = 129
The solution of 8x + 1 = 129 is x = 16.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 1 from both sides:
- 3
Divide both sides by 8:
- 4
Check: put x = 16 back into the equation.
LaTeX source of the formulas on this page
\[ 8x + 1 = 129\ \Rightarrow\ x = 16 \]
\[ 8x + 1 = 129 \]
\[ 8x + 1 - 1 = 129 - 1 \ \Rightarrow\ 8x = 128 \]
\[ \frac{8x}{8} = \frac{128}{8} \ \Rightarrow\ x = 16 \]
\[ 8\cdot16 + 1 = 128 + 1 = 129 \checkmark \]Trying values of x in 8x + 1 = 129
| x | 8x + 1 | Equals 129? |
|---|---|---|
| 14 | 113 | no |
| 15 | 121 | no |
| 16 | 129 | yes |
| 17 | 137 | no |
| 18 | 145 | no |
Questions
What is x in 8x + 1 = 129?
The solution of 8x + 1 = 129 is x = 16.
How do you solve 8x + 1 = 129?
Subtract 1 from both sides to get 8x = 128, then divide both sides by 8 to get x = 16.
How do I check the answer?
Replace x by 16: 8(16) + 1 = 129, which is 129.