Solve 9x + 1 = 145
The solution of 9x + 1 = 145 is x = 16.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 1 from both sides:
- 3
Divide both sides by 9:
- 4
Check: put x = 16 back into the equation.
LaTeX source of the formulas on this page
\[ 9x + 1 = 145\ \Rightarrow\ x = 16 \]
\[ 9x + 1 = 145 \]
\[ 9x + 1 - 1 = 145 - 1 \ \Rightarrow\ 9x = 144 \]
\[ \frac{9x}{9} = \frac{144}{9} \ \Rightarrow\ x = 16 \]
\[ 9\cdot16 + 1 = 144 + 1 = 145 \checkmark \]Trying values of x in 9x + 1 = 145
| x | 9x + 1 | Equals 145? |
|---|---|---|
| 14 | 127 | no |
| 15 | 136 | no |
| 16 | 145 | yes |
| 17 | 154 | no |
| 18 | 163 | no |
Questions
What is x in 9x + 1 = 145?
The solution of 9x + 1 = 145 is x = 16.
How do you solve 9x + 1 = 145?
Subtract 1 from both sides to get 9x = 144, then divide both sides by 9 to get x = 16.
How do I check the answer?
Replace x by 16: 9(16) + 1 = 145, which is 145.