Solve 8x ā 2 = ā42
The solution of 8x ā 2 = ā42 is x = -5.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.
- 2
Add 2 to both sides:
- 3
Divide both sides by 8:
- 4
Check: put x = -5 back into the equation.
LaTeX source of the formulas on this page
\[ 8x - 2 = -42\ \Rightarrow\ x = -5 \]
\[ 8x - 2 = -42 \]
\[ 8x - 2 + 2 = -42 + 2 \ \Rightarrow\ 8x = -40 \]
\[ \frac{8x}{8} = \frac{-40}{8} \ \Rightarrow\ x = -5 \]
\[ 8\cdot(-5) - 2 = -40 - 2 = -42 \checkmark \]Trying values of x in 8x ā 2 = ā42
| x | 8x ā 2 | Equals -42? |
|---|---|---|
| -7 | -58 | no |
| -6 | -50 | no |
| -5 | -42 | yes |
| -4 | -34 | no |
| -3 | -26 | no |
Questions
What is x in 8x ā 2 = ā42?
The solution of 8x ā 2 = ā42 is x = -5.
How do you solve 8x ā 2 = ā42?
Add 2 to both sides to get 8x = -40, then divide both sides by 8 to get x = -5.
How do I check the answer?
Replace x by -5: 8(-5) ā 2 = -42, which is -42.