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Solve 8x āˆ’ 2 = āˆ’42

The solution of 8x āˆ’ 2 = āˆ’42 is x = -5.

The lines y = 8x āˆ’ 2 and y = -42 meet at x = -5-10-8-6-4-2-80-60-40-20x = -5y = 8x āˆ’ 2y = -42
The lines y = 8x āˆ’ 2 and y = -42 meet at x = -5. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    8xāˆ’2=āˆ’428x - 2 = -42
  2. 2

    Add 2 to both sides:

    8xāˆ’2+2=āˆ’42+2 ⇒ 8x=āˆ’408x - 2 + 2 = -42 + 2 \ \Rightarrow\ 8x = -40
  3. 3

    Divide both sides by 8:

    8x8=āˆ’408 ⇒ x=āˆ’5\frac{8x}{8} = \frac{-40}{8} \ \Rightarrow\ x = -5
  4. 4

    Check: put x = -5 back into the equation.

    8ā‹…(āˆ’5)āˆ’2=āˆ’40āˆ’2=āˆ’42āœ“8\cdot(-5) - 2 = -40 - 2 = -42 \checkmark
LaTeX source of the formulas on this page
\[ 8x - 2 = -42\ \Rightarrow\ x = -5 \]
\[ 8x - 2 = -42 \]
\[ 8x - 2 + 2 = -42 + 2 \ \Rightarrow\ 8x = -40 \]
\[ \frac{8x}{8} = \frac{-40}{8} \ \Rightarrow\ x = -5 \]
\[ 8\cdot(-5) - 2 = -40 - 2 = -42 \checkmark \]

Trying values of x in 8x āˆ’ 2 = āˆ’42

x8x āˆ’ 2Equals -42?
-7-58no
-6-50no
-5-42yes
-4-34no
-3-26no

Questions

What is x in 8x āˆ’ 2 = āˆ’42?

The solution of 8x āˆ’ 2 = āˆ’42 is x = -5.

How do you solve 8x āˆ’ 2 = āˆ’42?

Add 2 to both sides to get 8x = -40, then divide both sides by 8 to get x = -5.

How do I check the answer?

Replace x by -5: 8(-5) āˆ’ 2 = -42, which is -42.

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    Solve 8x āˆ’ 2 = āˆ’42: x = -5 (steps and check) | WordGPT