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Solve 8x āˆ’ 15 = āˆ’7

The solution of 8x āˆ’ 15 = āˆ’7 is x = 1.

The lines y = 8x āˆ’ 15 and y = -7 meet at x = 1-4-2246-60-40-202040x = 1y = 8x āˆ’ 15y = -7
The lines y = 8x āˆ’ 15 and y = -7 meet at x = 1. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    8xāˆ’15=āˆ’78x - 15 = -7
  2. 2

    Add 15 to both sides:

    8xāˆ’15+15=āˆ’7+15 ⇒ 8x=88x - 15 + 15 = -7 + 15 \ \Rightarrow\ 8x = 8
  3. 3

    Divide both sides by 8:

    8x8=88 ⇒ x=1\frac{8x}{8} = \frac{8}{8} \ \Rightarrow\ x = 1
  4. 4

    Check: put x = 1 back into the equation.

    8ā‹…1āˆ’15=8āˆ’15=āˆ’7āœ“8\cdot1 - 15 = 8 - 15 = -7 \checkmark
LaTeX source of the formulas on this page
\[ 8x - 15 = -7\ \Rightarrow\ x = 1 \]
\[ 8x - 15 = -7 \]
\[ 8x - 15 + 15 = -7 + 15 \ \Rightarrow\ 8x = 8 \]
\[ \frac{8x}{8} = \frac{8}{8} \ \Rightarrow\ x = 1 \]
\[ 8\cdot1 - 15 = 8 - 15 = -7 \checkmark \]

Trying values of x in 8x āˆ’ 15 = āˆ’7

x8x āˆ’ 15Equals -7?
-1-23no
0-15no
1-7yes
21no
39no

Questions

What is x in 8x āˆ’ 15 = āˆ’7?

The solution of 8x āˆ’ 15 = āˆ’7 is x = 1.

How do you solve 8x āˆ’ 15 = āˆ’7?

Add 15 to both sides to get 8x = 8, then divide both sides by 8 to get x = 1.

How do I check the answer?

Replace x by 1: 8(1) āˆ’ 15 = -7, which is -7.

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    Solve 8x āˆ’ 15 = āˆ’7: x = 1 (steps and check) | WordGPT