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Solve 8x āˆ’ 15 = āˆ’15

The solution of 8x āˆ’ 15 = āˆ’15 is x = 0.

The lines y = 8x āˆ’ 15 and y = -15 meet at x = 0-6-4-2246-60-40-202040x = 0y = 8x āˆ’ 15y = -15
The lines y = 8x āˆ’ 15 and y = -15 meet at x = 0. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    8xāˆ’15=āˆ’158x - 15 = -15
  2. 2

    Add 15 to both sides:

    8xāˆ’15+15=āˆ’15+15 ⇒ 8x=08x - 15 + 15 = -15 + 15 \ \Rightarrow\ 8x = 0
  3. 3

    Divide both sides by 8:

    8x8=08 ⇒ x=0\frac{8x}{8} = \frac{0}{8} \ \Rightarrow\ x = 0
  4. 4

    Check: put x = 0 back into the equation.

    8ā‹…0āˆ’15=0āˆ’15=āˆ’15āœ“8\cdot0 - 15 = 0 - 15 = -15 \checkmark
LaTeX source of the formulas on this page
\[ 8x - 15 = -15\ \Rightarrow\ x = 0 \]
\[ 8x - 15 = -15 \]
\[ 8x - 15 + 15 = -15 + 15 \ \Rightarrow\ 8x = 0 \]
\[ \frac{8x}{8} = \frac{0}{8} \ \Rightarrow\ x = 0 \]
\[ 8\cdot0 - 15 = 0 - 15 = -15 \checkmark \]

Trying values of x in 8x āˆ’ 15 = āˆ’15

x8x āˆ’ 15Equals -15?
-2-31no
-1-23no
0-15yes
1-7no
21no

Questions

What is x in 8x āˆ’ 15 = āˆ’15?

The solution of 8x āˆ’ 15 = āˆ’15 is x = 0.

How do you solve 8x āˆ’ 15 = āˆ’15?

Add 15 to both sides to get 8x = 0, then divide both sides by 8 to get x = 0.

How do I check the answer?

Replace x by 0: 8(0) āˆ’ 15 = -15, which is -15.

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    Solve 8x āˆ’ 15 = āˆ’15: x = 0 (steps and check) | WordGPT