Solve 7x + 15 = 1
The solution of 7x + 15 = 1 is x = -2.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 15 from both sides:
- 3
Divide both sides by 7:
- 4
Check: put x = -2 back into the equation.
LaTeX source of the formulas on this page
\[ 7x + 15 = 1\ \Rightarrow\ x = -2 \]
\[ 7x + 15 = 1 \]
\[ 7x + 15 - 15 = 1 - 15 \ \Rightarrow\ 7x = -14 \]
\[ \frac{7x}{7} = \frac{-14}{7} \ \Rightarrow\ x = -2 \]
\[ 7\cdot(-2) + 15 = -14 + 15 = 1 \checkmark \]Trying values of x in 7x + 15 = 1
| x | 7x + 15 | Equals 1? |
|---|---|---|
| -4 | -13 | no |
| -3 | -6 | no |
| -2 | 1 | yes |
| -1 | 8 | no |
| 0 | 15 | no |
Questions
What is x in 7x + 15 = 1?
The solution of 7x + 15 = 1 is x = -2.
How do you solve 7x + 15 = 1?
Subtract 15 from both sides to get 7x = -14, then divide both sides by 7 to get x = -2.
How do I check the answer?
Replace x by -2: 7(-2) + 15 = 1, which is 1.