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Solve 8x + 15 = āˆ’1

The solution of 8x + 15 = āˆ’1 is x = -2.

The lines y = 8x + 15 and y = -1 meet at x = -2-8-6-4-224-40-202040x = -2y = 8x + 15y = -1
The lines y = 8x + 15 and y = -1 meet at x = -2. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    8x+15=āˆ’18x + 15 = -1
  2. 2

    Subtract 15 from both sides:

    8x+15āˆ’15=āˆ’1āˆ’15 ⇒ 8x=āˆ’168x + 15 - 15 = -1 - 15 \ \Rightarrow\ 8x = -16
  3. 3

    Divide both sides by 8:

    8x8=āˆ’168 ⇒ x=āˆ’2\frac{8x}{8} = \frac{-16}{8} \ \Rightarrow\ x = -2
  4. 4

    Check: put x = -2 back into the equation.

    8ā‹…(āˆ’2)+15=āˆ’16+15=āˆ’1āœ“8\cdot(-2) + 15 = -16 + 15 = -1 \checkmark
LaTeX source of the formulas on this page
\[ 8x + 15 = -1\ \Rightarrow\ x = -2 \]
\[ 8x + 15 = -1 \]
\[ 8x + 15 - 15 = -1 - 15 \ \Rightarrow\ 8x = -16 \]
\[ \frac{8x}{8} = \frac{-16}{8} \ \Rightarrow\ x = -2 \]
\[ 8\cdot(-2) + 15 = -16 + 15 = -1 \checkmark \]

Trying values of x in 8x + 15 = āˆ’1

x8x + 15Equals -1?
-4-17no
-3-9no
-2-1yes
-17no
015no

Questions

What is x in 8x + 15 = āˆ’1?

The solution of 8x + 15 = āˆ’1 is x = -2.

How do you solve 8x + 15 = āˆ’1?

Subtract 15 from both sides to get 8x = -16, then divide both sides by 8 to get x = -2.

How do I check the answer?

Replace x by -2: 8(-2) + 15 = -1, which is -1.

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    Solve 8x + 15 = āˆ’1: x = -2 (steps and check) | WordGPT