Solve 8x + 15 = ā1
The solution of 8x + 15 = ā1 is x = -2.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 15 from both sides:
- 3
Divide both sides by 8:
- 4
Check: put x = -2 back into the equation.
LaTeX source of the formulas on this page
\[ 8x + 15 = -1\ \Rightarrow\ x = -2 \]
\[ 8x + 15 = -1 \]
\[ 8x + 15 - 15 = -1 - 15 \ \Rightarrow\ 8x = -16 \]
\[ \frac{8x}{8} = \frac{-16}{8} \ \Rightarrow\ x = -2 \]
\[ 8\cdot(-2) + 15 = -16 + 15 = -1 \checkmark \]Trying values of x in 8x + 15 = ā1
| x | 8x + 15 | Equals -1? |
|---|---|---|
| -4 | -17 | no |
| -3 | -9 | no |
| -2 | -1 | yes |
| -1 | 7 | no |
| 0 | 15 | no |
Questions
What is x in 8x + 15 = ā1?
The solution of 8x + 15 = ā1 is x = -2.
How do you solve 8x + 15 = ā1?
Subtract 15 from both sides to get 8x = -16, then divide both sides by 8 to get x = -2.
How do I check the answer?
Replace x by -2: 8(-2) + 15 = -1, which is -1.