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Solve 7x + 1 = āˆ’41

The solution of 7x + 1 = āˆ’41 is x = -6.

The lines y = 7x + 1 and y = -41 meet at x = -6-12-10-8-6-4-2-80-60-40-20x = -6y = 7x + 1y = -41
The lines y = 7x + 1 and y = -41 meet at x = -6. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    7x+1=āˆ’417x + 1 = -41
  2. 2

    Subtract 1 from both sides:

    7x+1āˆ’1=āˆ’41āˆ’1 ⇒ 7x=āˆ’427x + 1 - 1 = -41 - 1 \ \Rightarrow\ 7x = -42
  3. 3

    Divide both sides by 7:

    7x7=āˆ’427 ⇒ x=āˆ’6\frac{7x}{7} = \frac{-42}{7} \ \Rightarrow\ x = -6
  4. 4

    Check: put x = -6 back into the equation.

    7ā‹…(āˆ’6)+1=āˆ’42+1=āˆ’41āœ“7\cdot(-6) + 1 = -42 + 1 = -41 \checkmark
LaTeX source of the formulas on this page
\[ 7x + 1 = -41\ \Rightarrow\ x = -6 \]
\[ 7x + 1 = -41 \]
\[ 7x + 1 - 1 = -41 - 1 \ \Rightarrow\ 7x = -42 \]
\[ \frac{7x}{7} = \frac{-42}{7} \ \Rightarrow\ x = -6 \]
\[ 7\cdot(-6) + 1 = -42 + 1 = -41 \checkmark \]

Trying values of x in 7x + 1 = āˆ’41

x7x + 1Equals -41?
-8-55no
-7-48no
-6-41yes
-5-34no
-4-27no

Questions

What is x in 7x + 1 = āˆ’41?

The solution of 7x + 1 = āˆ’41 is x = -6.

How do you solve 7x + 1 = āˆ’41?

Subtract 1 from both sides to get 7x = -42, then divide both sides by 7 to get x = -6.

How do I check the answer?

Replace x by -6: 7(-6) + 1 = -41, which is -41.

Similar equations

    Solve 7x + 1 = āˆ’41: x = -6 (steps and check) | WordGPT