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Solve 8x + 1 = āˆ’47

The solution of 8x + 1 = āˆ’47 is x = -6.

The lines y = 8x + 1 and y = -47 meet at x = -6-12-10-8-6-4-2-100-80-60-40-20x = -6y = 8x + 1y = -47
The lines y = 8x + 1 and y = -47 meet at x = -6. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    8x+1=āˆ’478x + 1 = -47
  2. 2

    Subtract 1 from both sides:

    8x+1āˆ’1=āˆ’47āˆ’1 ⇒ 8x=āˆ’488x + 1 - 1 = -47 - 1 \ \Rightarrow\ 8x = -48
  3. 3

    Divide both sides by 8:

    8x8=āˆ’488 ⇒ x=āˆ’6\frac{8x}{8} = \frac{-48}{8} \ \Rightarrow\ x = -6
  4. 4

    Check: put x = -6 back into the equation.

    8ā‹…(āˆ’6)+1=āˆ’48+1=āˆ’47āœ“8\cdot(-6) + 1 = -48 + 1 = -47 \checkmark
LaTeX source of the formulas on this page
\[ 8x + 1 = -47\ \Rightarrow\ x = -6 \]
\[ 8x + 1 = -47 \]
\[ 8x + 1 - 1 = -47 - 1 \ \Rightarrow\ 8x = -48 \]
\[ \frac{8x}{8} = \frac{-48}{8} \ \Rightarrow\ x = -6 \]
\[ 8\cdot(-6) + 1 = -48 + 1 = -47 \checkmark \]

Trying values of x in 8x + 1 = āˆ’47

x8x + 1Equals -47?
-8-63no
-7-55no
-6-47yes
-5-39no
-4-31no

Questions

What is x in 8x + 1 = āˆ’47?

The solution of 8x + 1 = āˆ’47 is x = -6.

How do you solve 8x + 1 = āˆ’47?

Subtract 1 from both sides to get 8x = -48, then divide both sides by 8 to get x = -6.

How do I check the answer?

Replace x by -6: 8(-6) + 1 = -47, which is -47.

Similar equations

    Solve 8x + 1 = āˆ’47: x = -6 (steps and check) | WordGPT