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Solve 7x + 1 = āˆ’13

The solution of 7x + 1 = āˆ’13 is x = -2.

The lines y = 7x + 1 and y = -13 meet at x = -2-8-6-4-224-60-40-2020x = -2y = 7x + 1y = -13
The lines y = 7x + 1 and y = -13 meet at x = -2. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    7x+1=āˆ’137x + 1 = -13
  2. 2

    Subtract 1 from both sides:

    7x+1āˆ’1=āˆ’13āˆ’1 ⇒ 7x=āˆ’147x + 1 - 1 = -13 - 1 \ \Rightarrow\ 7x = -14
  3. 3

    Divide both sides by 7:

    7x7=āˆ’147 ⇒ x=āˆ’2\frac{7x}{7} = \frac{-14}{7} \ \Rightarrow\ x = -2
  4. 4

    Check: put x = -2 back into the equation.

    7ā‹…(āˆ’2)+1=āˆ’14+1=āˆ’13āœ“7\cdot(-2) + 1 = -14 + 1 = -13 \checkmark
LaTeX source of the formulas on this page
\[ 7x + 1 = -13\ \Rightarrow\ x = -2 \]
\[ 7x + 1 = -13 \]
\[ 7x + 1 - 1 = -13 - 1 \ \Rightarrow\ 7x = -14 \]
\[ \frac{7x}{7} = \frac{-14}{7} \ \Rightarrow\ x = -2 \]
\[ 7\cdot(-2) + 1 = -14 + 1 = -13 \checkmark \]

Trying values of x in 7x + 1 = āˆ’13

x7x + 1Equals -13?
-4-27no
-3-20no
-2-13yes
-1-6no
01no

Questions

What is x in 7x + 1 = āˆ’13?

The solution of 7x + 1 = āˆ’13 is x = -2.

How do you solve 7x + 1 = āˆ’13?

Subtract 1 from both sides to get 7x = -14, then divide both sides by 7 to get x = -2.

How do I check the answer?

Replace x by -2: 7(-2) + 1 = -13, which is -13.

Similar equations

    Solve 7x + 1 = āˆ’13: x = -2 (steps and check) | WordGPT