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Solve 7x āˆ’ 11 = 45

The solution of 7x āˆ’ 11 = 45 is x = 8.

The lines y = 7x āˆ’ 11 and y = 45 meet at x = 8246810121420406080x = 8y = 7x āˆ’ 11y = 45
The lines y = 7x āˆ’ 11 and y = 45 meet at x = 8. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    7xāˆ’11=457x - 11 = 45
  2. 2

    Add 11 to both sides:

    7xāˆ’11+11=45+11 ⇒ 7x=567x - 11 + 11 = 45 + 11 \ \Rightarrow\ 7x = 56
  3. 3

    Divide both sides by 7:

    7x7=567 ⇒ x=8\frac{7x}{7} = \frac{56}{7} \ \Rightarrow\ x = 8
  4. 4

    Check: put x = 8 back into the equation.

    7ā‹…8āˆ’11=56āˆ’11=45āœ“7\cdot8 - 11 = 56 - 11 = 45 \checkmark
LaTeX source of the formulas on this page
\[ 7x - 11 = 45\ \Rightarrow\ x = 8 \]
\[ 7x - 11 = 45 \]
\[ 7x - 11 + 11 = 45 + 11 \ \Rightarrow\ 7x = 56 \]
\[ \frac{7x}{7} = \frac{56}{7} \ \Rightarrow\ x = 8 \]
\[ 7\cdot8 - 11 = 56 - 11 = 45 \checkmark \]

Trying values of x in 7x āˆ’ 11 = 45

x7x āˆ’ 11Equals 45?
631no
738no
845yes
952no
1059no

Questions

What is x in 7x āˆ’ 11 = 45?

The solution of 7x āˆ’ 11 = 45 is x = 8.

How do you solve 7x āˆ’ 11 = 45?

Add 11 to both sides to get 7x = 56, then divide both sides by 7 to get x = 8.

How do I check the answer?

Replace x by 8: 7(8) āˆ’ 11 = 45, which is 45.

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