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Solve 7x āˆ’ 11 = 38

The solution of 7x āˆ’ 11 = 38 is x = 7.

The lines y = 7x āˆ’ 11 and y = 38 meet at x = 72468101220406080x = 7y = 7x āˆ’ 11y = 38
The lines y = 7x āˆ’ 11 and y = 38 meet at x = 7. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    7xāˆ’11=387x - 11 = 38
  2. 2

    Add 11 to both sides:

    7xāˆ’11+11=38+11 ⇒ 7x=497x - 11 + 11 = 38 + 11 \ \Rightarrow\ 7x = 49
  3. 3

    Divide both sides by 7:

    7x7=497 ⇒ x=7\frac{7x}{7} = \frac{49}{7} \ \Rightarrow\ x = 7
  4. 4

    Check: put x = 7 back into the equation.

    7ā‹…7āˆ’11=49āˆ’11=38āœ“7\cdot7 - 11 = 49 - 11 = 38 \checkmark
LaTeX source of the formulas on this page
\[ 7x - 11 = 38\ \Rightarrow\ x = 7 \]
\[ 7x - 11 = 38 \]
\[ 7x - 11 + 11 = 38 + 11 \ \Rightarrow\ 7x = 49 \]
\[ \frac{7x}{7} = \frac{49}{7} \ \Rightarrow\ x = 7 \]
\[ 7\cdot7 - 11 = 49 - 11 = 38 \checkmark \]

Trying values of x in 7x āˆ’ 11 = 38

x7x āˆ’ 11Equals 38?
524no
631no
738yes
845no
952no

Questions

What is x in 7x āˆ’ 11 = 38?

The solution of 7x āˆ’ 11 = 38 is x = 7.

How do you solve 7x āˆ’ 11 = 38?

Add 11 to both sides to get 7x = 49, then divide both sides by 7 to get x = 7.

How do I check the answer?

Replace x by 7: 7(7) āˆ’ 11 = 38, which is 38.

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