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Solve 7x āˆ’ 10 = āˆ’52

The solution of 7x āˆ’ 10 = āˆ’52 is x = -6.

The lines y = 7x āˆ’ 10 and y = -52 meet at x = -6-12-10-8-6-4-2-100-80-60-40-20x = -6y = 7x āˆ’ 10y = -52
The lines y = 7x āˆ’ 10 and y = -52 meet at x = -6. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    7xāˆ’10=āˆ’527x - 10 = -52
  2. 2

    Add 10 to both sides:

    7xāˆ’10+10=āˆ’52+10 ⇒ 7x=āˆ’427x - 10 + 10 = -52 + 10 \ \Rightarrow\ 7x = -42
  3. 3

    Divide both sides by 7:

    7x7=āˆ’427 ⇒ x=āˆ’6\frac{7x}{7} = \frac{-42}{7} \ \Rightarrow\ x = -6
  4. 4

    Check: put x = -6 back into the equation.

    7ā‹…(āˆ’6)āˆ’10=āˆ’42āˆ’10=āˆ’52āœ“7\cdot(-6) - 10 = -42 - 10 = -52 \checkmark
LaTeX source of the formulas on this page
\[ 7x - 10 = -52\ \Rightarrow\ x = -6 \]
\[ 7x - 10 = -52 \]
\[ 7x - 10 + 10 = -52 + 10 \ \Rightarrow\ 7x = -42 \]
\[ \frac{7x}{7} = \frac{-42}{7} \ \Rightarrow\ x = -6 \]
\[ 7\cdot(-6) - 10 = -42 - 10 = -52 \checkmark \]

Trying values of x in 7x āˆ’ 10 = āˆ’52

x7x āˆ’ 10Equals -52?
-8-66no
-7-59no
-6-52yes
-5-45no
-4-38no

Questions

What is x in 7x āˆ’ 10 = āˆ’52?

The solution of 7x āˆ’ 10 = āˆ’52 is x = -6.

How do you solve 7x āˆ’ 10 = āˆ’52?

Add 10 to both sides to get 7x = -42, then divide both sides by 7 to get x = -6.

How do I check the answer?

Replace x by -6: 7(-6) āˆ’ 10 = -52, which is -52.

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    Solve 7x āˆ’ 10 = āˆ’52: x = -6 (steps and check) | WordGPT