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Solve 6x + 2 = āˆ’4

The solution of 6x + 2 = āˆ’4 is x = -1.

The lines y = 6x + 2 and y = -4 meet at x = -1-6-4-224-40-30-20-10102030x = -1y = 6x + 2y = -4
The lines y = 6x + 2 and y = -4 meet at x = -1. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    6x+2=āˆ’46x + 2 = -4
  2. 2

    Subtract 2 from both sides:

    6x+2āˆ’2=āˆ’4āˆ’2 ⇒ 6x=āˆ’66x + 2 - 2 = -4 - 2 \ \Rightarrow\ 6x = -6
  3. 3

    Divide both sides by 6:

    6x6=āˆ’66 ⇒ x=āˆ’1\frac{6x}{6} = \frac{-6}{6} \ \Rightarrow\ x = -1
  4. 4

    Check: put x = -1 back into the equation.

    6ā‹…(āˆ’1)+2=āˆ’6+2=āˆ’4āœ“6\cdot(-1) + 2 = -6 + 2 = -4 \checkmark
LaTeX source of the formulas on this page
\[ 6x + 2 = -4\ \Rightarrow\ x = -1 \]
\[ 6x + 2 = -4 \]
\[ 6x + 2 - 2 = -4 - 2 \ \Rightarrow\ 6x = -6 \]
\[ \frac{6x}{6} = \frac{-6}{6} \ \Rightarrow\ x = -1 \]
\[ 6\cdot(-1) + 2 = -6 + 2 = -4 \checkmark \]

Trying values of x in 6x + 2 = āˆ’4

x6x + 2Equals -4?
-3-16no
-2-10no
-1-4yes
02no
18no

Questions

What is x in 6x + 2 = āˆ’4?

The solution of 6x + 2 = āˆ’4 is x = -1.

How do you solve 6x + 2 = āˆ’4?

Subtract 2 from both sides to get 6x = -6, then divide both sides by 6 to get x = -1.

How do I check the answer?

Replace x by -1: 6(-1) + 2 = -4, which is -4.

Similar equations

    Solve 6x + 2 = āˆ’4: x = -1 (steps and check) | WordGPT