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Solve 6x + 2 = āˆ’10

The solution of 6x + 2 = āˆ’10 is x = -2.

The lines y = 6x + 2 and y = -10 meet at x = -2-8-6-4-224-50-40-30-20-10102030x = -2y = 6x + 2y = -10
The lines y = 6x + 2 and y = -10 meet at x = -2. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    6x+2=āˆ’106x + 2 = -10
  2. 2

    Subtract 2 from both sides:

    6x+2āˆ’2=āˆ’10āˆ’2 ⇒ 6x=āˆ’126x + 2 - 2 = -10 - 2 \ \Rightarrow\ 6x = -12
  3. 3

    Divide both sides by 6:

    6x6=āˆ’126 ⇒ x=āˆ’2\frac{6x}{6} = \frac{-12}{6} \ \Rightarrow\ x = -2
  4. 4

    Check: put x = -2 back into the equation.

    6ā‹…(āˆ’2)+2=āˆ’12+2=āˆ’10āœ“6\cdot(-2) + 2 = -12 + 2 = -10 \checkmark
LaTeX source of the formulas on this page
\[ 6x + 2 = -10\ \Rightarrow\ x = -2 \]
\[ 6x + 2 = -10 \]
\[ 6x + 2 - 2 = -10 - 2 \ \Rightarrow\ 6x = -12 \]
\[ \frac{6x}{6} = \frac{-12}{6} \ \Rightarrow\ x = -2 \]
\[ 6\cdot(-2) + 2 = -12 + 2 = -10 \checkmark \]

Trying values of x in 6x + 2 = āˆ’10

x6x + 2Equals -10?
-4-22no
-3-16no
-2-10yes
-1-4no
02no

Questions

What is x in 6x + 2 = āˆ’10?

The solution of 6x + 2 = āˆ’10 is x = -2.

How do you solve 6x + 2 = āˆ’10?

Subtract 2 from both sides to get 6x = -12, then divide both sides by 6 to get x = -2.

How do I check the answer?

Replace x by -2: 6(-2) + 2 = -10, which is -10.

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    Solve 6x + 2 = āˆ’10: x = -2 (steps and check) | WordGPT