Solve 6x + 2 = ā10
The solution of 6x + 2 = ā10 is x = -2.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 2 from both sides:
- 3
Divide both sides by 6:
- 4
Check: put x = -2 back into the equation.
LaTeX source of the formulas on this page
\[ 6x + 2 = -10\ \Rightarrow\ x = -2 \]
\[ 6x + 2 = -10 \]
\[ 6x + 2 - 2 = -10 - 2 \ \Rightarrow\ 6x = -12 \]
\[ \frac{6x}{6} = \frac{-12}{6} \ \Rightarrow\ x = -2 \]
\[ 6\cdot(-2) + 2 = -12 + 2 = -10 \checkmark \]Trying values of x in 6x + 2 = ā10
| x | 6x + 2 | Equals -10? |
|---|---|---|
| -4 | -22 | no |
| -3 | -16 | no |
| -2 | -10 | yes |
| -1 | -4 | no |
| 0 | 2 | no |
Questions
What is x in 6x + 2 = ā10?
The solution of 6x + 2 = ā10 is x = -2.
How do you solve 6x + 2 = ā10?
Subtract 2 from both sides to get 6x = -12, then divide both sides by 6 to get x = -2.
How do I check the answer?
Replace x by -2: 6(-2) + 2 = -10, which is -10.