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Solve 6x + 10 = āˆ’38

The solution of 6x + 10 = āˆ’38 is x = -8.

The lines y = 6x + 10 and y = -38 meet at x = -8-14-12-10-8-6-4-2-80-70-60-50-40-30-20-10x = -8y = 6x + 10y = -38
The lines y = 6x + 10 and y = -38 meet at x = -8. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    6x+10=āˆ’386x + 10 = -38
  2. 2

    Subtract 10 from both sides:

    6x+10āˆ’10=āˆ’38āˆ’10 ⇒ 6x=āˆ’486x + 10 - 10 = -38 - 10 \ \Rightarrow\ 6x = -48
  3. 3

    Divide both sides by 6:

    6x6=āˆ’486 ⇒ x=āˆ’8\frac{6x}{6} = \frac{-48}{6} \ \Rightarrow\ x = -8
  4. 4

    Check: put x = -8 back into the equation.

    6ā‹…(āˆ’8)+10=āˆ’48+10=āˆ’38āœ“6\cdot(-8) + 10 = -48 + 10 = -38 \checkmark
LaTeX source of the formulas on this page
\[ 6x + 10 = -38\ \Rightarrow\ x = -8 \]
\[ 6x + 10 = -38 \]
\[ 6x + 10 - 10 = -38 - 10 \ \Rightarrow\ 6x = -48 \]
\[ \frac{6x}{6} = \frac{-48}{6} \ \Rightarrow\ x = -8 \]
\[ 6\cdot(-8) + 10 = -48 + 10 = -38 \checkmark \]

Trying values of x in 6x + 10 = āˆ’38

x6x + 10Equals -38?
-10-50no
-9-44no
-8-38yes
-7-32no
-6-26no

Questions

What is x in 6x + 10 = āˆ’38?

The solution of 6x + 10 = āˆ’38 is x = -8.

How do you solve 6x + 10 = āˆ’38?

Subtract 10 from both sides to get 6x = -48, then divide both sides by 6 to get x = -8.

How do I check the answer?

Replace x by -8: 6(-8) + 10 = -38, which is -38.

Similar equations

    Solve 6x + 10 = āˆ’38: x = -8 (steps and check) | WordGPT