Solve 6x + 10 = ā32
The solution of 6x + 10 = ā32 is x = -7.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 10 from both sides:
- 3
Divide both sides by 6:
- 4
Check: put x = -7 back into the equation.
LaTeX source of the formulas on this page
\[ 6x + 10 = -32\ \Rightarrow\ x = -7 \]
\[ 6x + 10 = -32 \]
\[ 6x + 10 - 10 = -32 - 10 \ \Rightarrow\ 6x = -42 \]
\[ \frac{6x}{6} = \frac{-42}{6} \ \Rightarrow\ x = -7 \]
\[ 6\cdot(-7) + 10 = -42 + 10 = -32 \checkmark \]Trying values of x in 6x + 10 = ā32
| x | 6x + 10 | Equals -32? |
|---|---|---|
| -9 | -44 | no |
| -8 | -38 | no |
| -7 | -32 | yes |
| -6 | -26 | no |
| -5 | -20 | no |
Questions
What is x in 6x + 10 = ā32?
The solution of 6x + 10 = ā32 is x = -7.
How do you solve 6x + 10 = ā32?
Subtract 10 from both sides to get 6x = -42, then divide both sides by 6 to get x = -7.
How do I check the answer?
Replace x by -7: 6(-7) + 10 = -32, which is -32.