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Solve 6x + 10 = āˆ’2

The solution of 6x + 10 = āˆ’2 is x = -2.

The lines y = 6x + 10 and y = -2 meet at x = -2-8-6-4-224-40-30-20-1010203040x = -2y = 6x + 10y = -2
The lines y = 6x + 10 and y = -2 meet at x = -2. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    6x+10=āˆ’26x + 10 = -2
  2. 2

    Subtract 10 from both sides:

    6x+10āˆ’10=āˆ’2āˆ’10 ⇒ 6x=āˆ’126x + 10 - 10 = -2 - 10 \ \Rightarrow\ 6x = -12
  3. 3

    Divide both sides by 6:

    6x6=āˆ’126 ⇒ x=āˆ’2\frac{6x}{6} = \frac{-12}{6} \ \Rightarrow\ x = -2
  4. 4

    Check: put x = -2 back into the equation.

    6ā‹…(āˆ’2)+10=āˆ’12+10=āˆ’2āœ“6\cdot(-2) + 10 = -12 + 10 = -2 \checkmark
LaTeX source of the formulas on this page
\[ 6x + 10 = -2\ \Rightarrow\ x = -2 \]
\[ 6x + 10 = -2 \]
\[ 6x + 10 - 10 = -2 - 10 \ \Rightarrow\ 6x = -12 \]
\[ \frac{6x}{6} = \frac{-12}{6} \ \Rightarrow\ x = -2 \]
\[ 6\cdot(-2) + 10 = -12 + 10 = -2 \checkmark \]

Trying values of x in 6x + 10 = āˆ’2

x6x + 10Equals -2?
-4-14no
-3-8no
-2-2yes
-14no
010no

Questions

What is x in 6x + 10 = āˆ’2?

The solution of 6x + 10 = āˆ’2 is x = -2.

How do you solve 6x + 10 = āˆ’2?

Subtract 10 from both sides to get 6x = -12, then divide both sides by 6 to get x = -2.

How do I check the answer?

Replace x by -2: 6(-2) + 10 = -2, which is -2.

Similar equations

    Solve 6x + 10 = āˆ’2: x = -2 (steps and check) | WordGPT