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Solve 6x āˆ’ 10 = āˆ’22

The solution of 6x āˆ’ 10 = āˆ’22 is x = -2.

The lines y = 6x āˆ’ 10 and y = -22 meet at x = -2-8-6-4-224-60-50-40-30-20-101020x = -2y = 6x āˆ’ 10y = -22
The lines y = 6x āˆ’ 10 and y = -22 meet at x = -2. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    6xāˆ’10=āˆ’226x - 10 = -22
  2. 2

    Add 10 to both sides:

    6xāˆ’10+10=āˆ’22+10 ⇒ 6x=āˆ’126x - 10 + 10 = -22 + 10 \ \Rightarrow\ 6x = -12
  3. 3

    Divide both sides by 6:

    6x6=āˆ’126 ⇒ x=āˆ’2\frac{6x}{6} = \frac{-12}{6} \ \Rightarrow\ x = -2
  4. 4

    Check: put x = -2 back into the equation.

    6ā‹…(āˆ’2)āˆ’10=āˆ’12āˆ’10=āˆ’22āœ“6\cdot(-2) - 10 = -12 - 10 = -22 \checkmark
LaTeX source of the formulas on this page
\[ 6x - 10 = -22\ \Rightarrow\ x = -2 \]
\[ 6x - 10 = -22 \]
\[ 6x - 10 + 10 = -22 + 10 \ \Rightarrow\ 6x = -12 \]
\[ \frac{6x}{6} = \frac{-12}{6} \ \Rightarrow\ x = -2 \]
\[ 6\cdot(-2) - 10 = -12 - 10 = -22 \checkmark \]

Trying values of x in 6x āˆ’ 10 = āˆ’22

x6x āˆ’ 10Equals -22?
-4-34no
-3-28no
-2-22yes
-1-16no
0-10no

Questions

What is x in 6x āˆ’ 10 = āˆ’22?

The solution of 6x āˆ’ 10 = āˆ’22 is x = -2.

How do you solve 6x āˆ’ 10 = āˆ’22?

Add 10 to both sides to get 6x = -12, then divide both sides by 6 to get x = -2.

How do I check the answer?

Replace x by -2: 6(-2) āˆ’ 10 = -22, which is -22.

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    Solve 6x āˆ’ 10 = āˆ’22: x = -2 (steps and check) | WordGPT