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Solve 6x āˆ’ 11 = 31

The solution of 6x āˆ’ 11 = 31 is x = 7.

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The lines y = 6x āˆ’ 11 and y = 31 meet at x = 724681012-1010203040506070x = 7y = 6x āˆ’ 11y = 31
The lines y = 6x āˆ’ 11 and y = 31 meet at x = 7. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    6xāˆ’11=316x - 11 = 31
  2. 2

    Add 11 to both sides:

    6xāˆ’11+11=31+11Ā ā‡’Ā 6x=426x - 11 + 11 = 31 + 11 \ \Rightarrow\ 6x = 42
  3. 3

    Divide both sides by 6:

    6x6=426Ā ā‡’Ā x=7\frac{6x}{6} = \frac{42}{6} \ \Rightarrow\ x = 7
  4. 4

    Check: put x = 7 back into the equation.

    6ā‹…7āˆ’11=42āˆ’11=31āœ“6\cdot7 - 11 = 42 - 11 = 31 \checkmark
LaTeX source of the formulas on this page
\[ 6x - 11 = 31\ \Rightarrow\ x = 7 \]
\[ 6x - 11 = 31 \]
\[ 6x - 11 + 11 = 31 + 11 \ \Rightarrow\ 6x = 42 \]
\[ \frac{6x}{6} = \frac{42}{6} \ \Rightarrow\ x = 7 \]
\[ 6\cdot7 - 11 = 42 - 11 = 31 \checkmark \]

Trying values of x in 6x āˆ’ 11 = 31

x6x āˆ’ 11Equals 31?
519no
625no
731yes
837no
943no

Questions

What is x in 6x āˆ’ 11 = 31?

The solution of 6x āˆ’ 11 = 31 is x = 7.

How do you solve 6x āˆ’ 11 = 31?

Add 11 to both sides to get 6x = 42, then divide both sides by 6 to get x = 7.

How do I check the answer?

Replace x by 7: 6(7) āˆ’ 11 = 31, which is 31.

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