Solve 5x + 2 = 27
The solution of 5x + 2 = 27 is x = 5.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 2 from both sides:
- 3
Divide both sides by 5:
- 4
Check: put x = 5 back into the equation.
LaTeX source of the formulas on this page
\[ 5x + 2 = 27\ \Rightarrow\ x = 5 \]
\[ 5x + 2 = 27 \]
\[ 5x + 2 - 2 = 27 - 2 \ \Rightarrow\ 5x = 25 \]
\[ \frac{5x}{5} = \frac{25}{5} \ \Rightarrow\ x = 5 \]
\[ 5\cdot5 + 2 = 25 + 2 = 27 \checkmark \]Trying values of x in 5x + 2 = 27
| x | 5x + 2 | Equals 27? |
|---|---|---|
| 3 | 17 | no |
| 4 | 22 | no |
| 5 | 27 | yes |
| 6 | 32 | no |
| 7 | 37 | no |
Questions
What is x in 5x + 2 = 27?
The solution of 5x + 2 = 27 is x = 5.
How do you solve 5x + 2 = 27?
Subtract 2 from both sides to get 5x = 25, then divide both sides by 5 to get x = 5.
How do I check the answer?
Replace x by 5: 5(5) + 2 = 27, which is 27.