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Solve 5x āˆ’ 2 = 23

The solution of 5x āˆ’ 2 = 23 is x = 5.

The lines y = 5x āˆ’ 2 and y = 23 meet at x = 5246810-101020304050x = 5y = 5x āˆ’ 2y = 23
The lines y = 5x āˆ’ 2 and y = 23 meet at x = 5. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    5xāˆ’2=235x - 2 = 23
  2. 2

    Add 2 to both sides:

    5xāˆ’2+2=23+2 ⇒ 5x=255x - 2 + 2 = 23 + 2 \ \Rightarrow\ 5x = 25
  3. 3

    Divide both sides by 5:

    5x5=255 ⇒ x=5\frac{5x}{5} = \frac{25}{5} \ \Rightarrow\ x = 5
  4. 4

    Check: put x = 5 back into the equation.

    5ā‹…5āˆ’2=25āˆ’2=23āœ“5\cdot5 - 2 = 25 - 2 = 23 \checkmark
LaTeX source of the formulas on this page
\[ 5x - 2 = 23\ \Rightarrow\ x = 5 \]
\[ 5x - 2 = 23 \]
\[ 5x - 2 + 2 = 23 + 2 \ \Rightarrow\ 5x = 25 \]
\[ \frac{5x}{5} = \frac{25}{5} \ \Rightarrow\ x = 5 \]
\[ 5\cdot5 - 2 = 25 - 2 = 23 \checkmark \]

Trying values of x in 5x āˆ’ 2 = 23

x5x āˆ’ 2Equals 23?
313no
418no
523yes
628no
733no

Questions

What is x in 5x āˆ’ 2 = 23?

The solution of 5x āˆ’ 2 = 23 is x = 5.

How do you solve 5x āˆ’ 2 = 23?

Add 2 to both sides to get 5x = 25, then divide both sides by 5 to get x = 5.

How do I check the answer?

Replace x by 5: 5(5) āˆ’ 2 = 23, which is 23.

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