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Solve 5x + 1 = āˆ’4

The solution of 5x + 1 = āˆ’4 is x = -1.

The lines y = 5x + 1 and y = -4 meet at x = -1-6-4-224-40-30-20-10102030x = -1y = 5x + 1y = -4
The lines y = 5x + 1 and y = -4 meet at x = -1. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    5x+1=āˆ’45x + 1 = -4
  2. 2

    Subtract 1 from both sides:

    5x+1āˆ’1=āˆ’4āˆ’1 ⇒ 5x=āˆ’55x + 1 - 1 = -4 - 1 \ \Rightarrow\ 5x = -5
  3. 3

    Divide both sides by 5:

    5x5=āˆ’55 ⇒ x=āˆ’1\frac{5x}{5} = \frac{-5}{5} \ \Rightarrow\ x = -1
  4. 4

    Check: put x = -1 back into the equation.

    5ā‹…(āˆ’1)+1=āˆ’5+1=āˆ’4āœ“5\cdot(-1) + 1 = -5 + 1 = -4 \checkmark
LaTeX source of the formulas on this page
\[ 5x + 1 = -4\ \Rightarrow\ x = -1 \]
\[ 5x + 1 = -4 \]
\[ 5x + 1 - 1 = -4 - 1 \ \Rightarrow\ 5x = -5 \]
\[ \frac{5x}{5} = \frac{-5}{5} \ \Rightarrow\ x = -1 \]
\[ 5\cdot(-1) + 1 = -5 + 1 = -4 \checkmark \]

Trying values of x in 5x + 1 = āˆ’4

x5x + 1Equals -4?
-3-14no
-2-9no
-1-4yes
01no
16no

Questions

What is x in 5x + 1 = āˆ’4?

The solution of 5x + 1 = āˆ’4 is x = -1.

How do you solve 5x + 1 = āˆ’4?

Subtract 1 from both sides to get 5x = -5, then divide both sides by 5 to get x = -1.

How do I check the answer?

Replace x by -1: 5(-1) + 1 = -4, which is -4.

Similar equations

    Solve 5x + 1 = āˆ’4: x = -1 (steps and check) | WordGPT