Solve 5x + 1 = ā4
The solution of 5x + 1 = ā4 is x = -1.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 1 from both sides:
- 3
Divide both sides by 5:
- 4
Check: put x = -1 back into the equation.
LaTeX source of the formulas on this page
\[ 5x + 1 = -4\ \Rightarrow\ x = -1 \]
\[ 5x + 1 = -4 \]
\[ 5x + 1 - 1 = -4 - 1 \ \Rightarrow\ 5x = -5 \]
\[ \frac{5x}{5} = \frac{-5}{5} \ \Rightarrow\ x = -1 \]
\[ 5\cdot(-1) + 1 = -5 + 1 = -4 \checkmark \]Trying values of x in 5x + 1 = ā4
| x | 5x + 1 | Equals -4? |
|---|---|---|
| -3 | -14 | no |
| -2 | -9 | no |
| -1 | -4 | yes |
| 0 | 1 | no |
| 1 | 6 | no |
Questions
What is x in 5x + 1 = ā4?
The solution of 5x + 1 = ā4 is x = -1.
How do you solve 5x + 1 = ā4?
Subtract 1 from both sides to get 5x = -5, then divide both sides by 5 to get x = -1.
How do I check the answer?
Replace x by -1: 5(-1) + 1 = -4, which is -4.