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Solve 6x + 1 = āˆ’5

The solution of 6x + 1 = āˆ’5 is x = -1.

The lines y = 6x + 1 and y = -5 meet at x = -1-6-4-224-40-30-20-10102030x = -1y = 6x + 1y = -5
The lines y = 6x + 1 and y = -5 meet at x = -1. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    6x+1=āˆ’56x + 1 = -5
  2. 2

    Subtract 1 from both sides:

    6x+1āˆ’1=āˆ’5āˆ’1 ⇒ 6x=āˆ’66x + 1 - 1 = -5 - 1 \ \Rightarrow\ 6x = -6
  3. 3

    Divide both sides by 6:

    6x6=āˆ’66 ⇒ x=āˆ’1\frac{6x}{6} = \frac{-6}{6} \ \Rightarrow\ x = -1
  4. 4

    Check: put x = -1 back into the equation.

    6ā‹…(āˆ’1)+1=āˆ’6+1=āˆ’5āœ“6\cdot(-1) + 1 = -6 + 1 = -5 \checkmark
LaTeX source of the formulas on this page
\[ 6x + 1 = -5\ \Rightarrow\ x = -1 \]
\[ 6x + 1 = -5 \]
\[ 6x + 1 - 1 = -5 - 1 \ \Rightarrow\ 6x = -6 \]
\[ \frac{6x}{6} = \frac{-6}{6} \ \Rightarrow\ x = -1 \]
\[ 6\cdot(-1) + 1 = -6 + 1 = -5 \checkmark \]

Trying values of x in 6x + 1 = āˆ’5

x6x + 1Equals -5?
-3-17no
-2-11no
-1-5yes
01no
17no

Questions

What is x in 6x + 1 = āˆ’5?

The solution of 6x + 1 = āˆ’5 is x = -1.

How do you solve 6x + 1 = āˆ’5?

Subtract 1 from both sides to get 6x = -6, then divide both sides by 6 to get x = -1.

How do I check the answer?

Replace x by -1: 6(-1) + 1 = -5, which is -5.

Similar equations

    Solve 6x + 1 = āˆ’5: x = -1 (steps and check) | WordGPT