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Solve 5x āˆ’ 12 = āˆ’62

The solution of 5x āˆ’ 12 = āˆ’62 is x = -10.

The lines y = 5x āˆ’ 12 and y = -62 meet at x = -10-16-14-12-10-8-6-4-90-80-70-60-50-40-30x = -10y = 5x āˆ’ 12y = -62
The lines y = 5x āˆ’ 12 and y = -62 meet at x = -10. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    5xāˆ’12=āˆ’625x - 12 = -62
  2. 2

    Add 12 to both sides:

    5xāˆ’12+12=āˆ’62+12 ⇒ 5x=āˆ’505x - 12 + 12 = -62 + 12 \ \Rightarrow\ 5x = -50
  3. 3

    Divide both sides by 5:

    5x5=āˆ’505 ⇒ x=āˆ’10\frac{5x}{5} = \frac{-50}{5} \ \Rightarrow\ x = -10
  4. 4

    Check: put x = -10 back into the equation.

    5ā‹…(āˆ’10)āˆ’12=āˆ’50āˆ’12=āˆ’62āœ“5\cdot(-10) - 12 = -50 - 12 = -62 \checkmark
LaTeX source of the formulas on this page
\[ 5x - 12 = -62\ \Rightarrow\ x = -10 \]
\[ 5x - 12 = -62 \]
\[ 5x - 12 + 12 = -62 + 12 \ \Rightarrow\ 5x = -50 \]
\[ \frac{5x}{5} = \frac{-50}{5} \ \Rightarrow\ x = -10 \]
\[ 5\cdot(-10) - 12 = -50 - 12 = -62 \checkmark \]

Trying values of x in 5x āˆ’ 12 = āˆ’62

x5x āˆ’ 12Equals -62?
-12-72no
-11-67no
-10-62yes
-9-57no
-8-52no

Questions

What is x in 5x āˆ’ 12 = āˆ’62?

The solution of 5x āˆ’ 12 = āˆ’62 is x = -10.

How do you solve 5x āˆ’ 12 = āˆ’62?

Add 12 to both sides to get 5x = -50, then divide both sides by 5 to get x = -10.

How do I check the answer?

Replace x by -10: 5(-10) āˆ’ 12 = -62, which is -62.

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    Solve 5x āˆ’ 12 = āˆ’62: x = -10 (steps and check) | WordGPT