Solve 4x + 8 = ā32
The solution of 4x + 8 = ā32 is x = -10.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 8 from both sides:
- 3
Divide both sides by 4:
- 4
Check: put x = -10 back into the equation.
LaTeX source of the formulas on this page
\[ 4x + 8 = -32\ \Rightarrow\ x = -10 \]
\[ 4x + 8 = -32 \]
\[ 4x + 8 - 8 = -32 - 8 \ \Rightarrow\ 4x = -40 \]
\[ \frac{4x}{4} = \frac{-40}{4} \ \Rightarrow\ x = -10 \]
\[ 4\cdot(-10) + 8 = -40 + 8 = -32 \checkmark \]Trying values of x in 4x + 8 = ā32
| x | 4x + 8 | Equals -32? |
|---|---|---|
| -12 | -40 | no |
| -11 | -36 | no |
| -10 | -32 | yes |
| -9 | -28 | no |
| -8 | -24 | no |
Questions
What is x in 4x + 8 = ā32?
The solution of 4x + 8 = ā32 is x = -10.
How do you solve 4x + 8 = ā32?
Subtract 8 from both sides to get 4x = -40, then divide both sides by 4 to get x = -10.
How do I check the answer?
Replace x by -10: 4(-10) + 8 = -32, which is -32.