Solve 5x + 8 = ā42
The solution of 5x + 8 = ā42 is x = -10.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 8 from both sides:
- 3
Divide both sides by 5:
- 4
Check: put x = -10 back into the equation.
LaTeX source of the formulas on this page
\[ 5x + 8 = -42\ \Rightarrow\ x = -10 \]
\[ 5x + 8 = -42 \]
\[ 5x + 8 - 8 = -42 - 8 \ \Rightarrow\ 5x = -50 \]
\[ \frac{5x}{5} = \frac{-50}{5} \ \Rightarrow\ x = -10 \]
\[ 5\cdot(-10) + 8 = -50 + 8 = -42 \checkmark \]Trying values of x in 5x + 8 = ā42
| x | 5x + 8 | Equals -42? |
|---|---|---|
| -12 | -52 | no |
| -11 | -47 | no |
| -10 | -42 | yes |
| -9 | -37 | no |
| -8 | -32 | no |
Questions
What is x in 5x + 8 = ā42?
The solution of 5x + 8 = ā42 is x = -10.
How do you solve 5x + 8 = ā42?
Subtract 8 from both sides to get 5x = -50, then divide both sides by 5 to get x = -10.
How do I check the answer?
Replace x by -10: 5(-10) + 8 = -42, which is -42.