Solve 4x + 4 = ā32
The solution of 4x + 4 = ā32 is x = -9.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 4 from both sides:
- 3
Divide both sides by 4:
- 4
Check: put x = -9 back into the equation.
LaTeX source of the formulas on this page
\[ 4x + 4 = -32\ \Rightarrow\ x = -9 \]
\[ 4x + 4 = -32 \]
\[ 4x + 4 - 4 = -32 - 4 \ \Rightarrow\ 4x = -36 \]
\[ \frac{4x}{4} = \frac{-36}{4} \ \Rightarrow\ x = -9 \]
\[ 4\cdot(-9) + 4 = -36 + 4 = -32 \checkmark \]Trying values of x in 4x + 4 = ā32
| x | 4x + 4 | Equals -32? |
|---|---|---|
| -11 | -40 | no |
| -10 | -36 | no |
| -9 | -32 | yes |
| -8 | -28 | no |
| -7 | -24 | no |
Questions
What is x in 4x + 4 = ā32?
The solution of 4x + 4 = ā32 is x = -9.
How do you solve 4x + 4 = ā32?
Subtract 4 from both sides to get 4x = -36, then divide both sides by 4 to get x = -9.
How do I check the answer?
Replace x by -9: 4(-9) + 4 = -32, which is -32.