Solve 4x + 4 = ā28
The solution of 4x + 4 = ā28 is x = -8.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 4 from both sides:
- 3
Divide both sides by 4:
- 4
Check: put x = -8 back into the equation.
LaTeX source of the formulas on this page
\[ 4x + 4 = -28\ \Rightarrow\ x = -8 \]
\[ 4x + 4 = -28 \]
\[ 4x + 4 - 4 = -28 - 4 \ \Rightarrow\ 4x = -32 \]
\[ \frac{4x}{4} = \frac{-32}{4} \ \Rightarrow\ x = -8 \]
\[ 4\cdot(-8) + 4 = -32 + 4 = -28 \checkmark \]Trying values of x in 4x + 4 = ā28
| x | 4x + 4 | Equals -28? |
|---|---|---|
| -10 | -36 | no |
| -9 | -32 | no |
| -8 | -28 | yes |
| -7 | -24 | no |
| -6 | -20 | no |
Questions
What is x in 4x + 4 = ā28?
The solution of 4x + 4 = ā28 is x = -8.
How do you solve 4x + 4 = ā28?
Subtract 4 from both sides to get 4x = -32, then divide both sides by 4 to get x = -8.
How do I check the answer?
Replace x by -8: 4(-8) + 4 = -28, which is -28.