Solve 4x + 12 = ā16
The solution of 4x + 12 = ā16 is x = -7.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 12 from both sides:
- 3
Divide both sides by 4:
- 4
Check: put x = -7 back into the equation.
LaTeX source of the formulas on this page
\[ 4x + 12 = -16\ \Rightarrow\ x = -7 \]
\[ 4x + 12 = -16 \]
\[ 4x + 12 - 12 = -16 - 12 \ \Rightarrow\ 4x = -28 \]
\[ \frac{4x}{4} = \frac{-28}{4} \ \Rightarrow\ x = -7 \]
\[ 4\cdot(-7) + 12 = -28 + 12 = -16 \checkmark \]Trying values of x in 4x + 12 = ā16
| x | 4x + 12 | Equals -16? |
|---|---|---|
| -9 | -24 | no |
| -8 | -20 | no |
| -7 | -16 | yes |
| -6 | -12 | no |
| -5 | -8 | no |
Questions
What is x in 4x + 12 = ā16?
The solution of 4x + 12 = ā16 is x = -7.
How do you solve 4x + 12 = ā16?
Subtract 12 from both sides to get 4x = -28, then divide both sides by 4 to get x = -7.
How do I check the answer?
Replace x by -7: 4(-7) + 12 = -16, which is -16.