Solve 4x ā 12 = ā40
The solution of 4x ā 12 = ā40 is x = -7.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.
- 2
Add 12 to both sides:
- 3
Divide both sides by 4:
- 4
Check: put x = -7 back into the equation.
LaTeX source of the formulas on this page
\[ 4x - 12 = -40\ \Rightarrow\ x = -7 \]
\[ 4x - 12 = -40 \]
\[ 4x - 12 + 12 = -40 + 12 \ \Rightarrow\ 4x = -28 \]
\[ \frac{4x}{4} = \frac{-28}{4} \ \Rightarrow\ x = -7 \]
\[ 4\cdot(-7) - 12 = -28 - 12 = -40 \checkmark \]Trying values of x in 4x ā 12 = ā40
| x | 4x ā 12 | Equals -40? |
|---|---|---|
| -9 | -48 | no |
| -8 | -44 | no |
| -7 | -40 | yes |
| -6 | -36 | no |
| -5 | -32 | no |
Questions
What is x in 4x ā 12 = ā40?
The solution of 4x ā 12 = ā40 is x = -7.
How do you solve 4x ā 12 = ā40?
Add 12 to both sides to get 4x = -28, then divide both sides by 4 to get x = -7.
How do I check the answer?
Replace x by -7: 4(-7) ā 12 = -40, which is -40.