Solve 4x + 1 = 33
The solution of 4x + 1 = 33 is x = 8.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 1 from both sides:
- 3
Divide both sides by 4:
- 4
Check: put x = 8 back into the equation.
LaTeX source of the formulas on this page
\[ 4x + 1 = 33\ \Rightarrow\ x = 8 \]
\[ 4x + 1 = 33 \]
\[ 4x + 1 - 1 = 33 - 1 \ \Rightarrow\ 4x = 32 \]
\[ \frac{4x}{4} = \frac{32}{4} \ \Rightarrow\ x = 8 \]
\[ 4\cdot8 + 1 = 32 + 1 = 33 \checkmark \]Trying values of x in 4x + 1 = 33
| x | 4x + 1 | Equals 33? |
|---|---|---|
| 6 | 25 | no |
| 7 | 29 | no |
| 8 | 33 | yes |
| 9 | 37 | no |
| 10 | 41 | no |
Questions
What is x in 4x + 1 = 33?
The solution of 4x + 1 = 33 is x = 8.
How do you solve 4x + 1 = 33?
Subtract 1 from both sides to get 4x = 32, then divide both sides by 4 to get x = 8.
How do I check the answer?
Replace x by 8: 4(8) + 1 = 33, which is 33.