Solve 5x + 1 = 41
The solution of 5x + 1 = 41 is x = 8.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 1 from both sides:
- 3
Divide both sides by 5:
- 4
Check: put x = 8 back into the equation.
LaTeX source of the formulas on this page
\[ 5x + 1 = 41\ \Rightarrow\ x = 8 \]
\[ 5x + 1 = 41 \]
\[ 5x + 1 - 1 = 41 - 1 \ \Rightarrow\ 5x = 40 \]
\[ \frac{5x}{5} = \frac{40}{5} \ \Rightarrow\ x = 8 \]
\[ 5\cdot8 + 1 = 40 + 1 = 41 \checkmark \]Trying values of x in 5x + 1 = 41
| x | 5x + 1 | Equals 41? |
|---|---|---|
| 6 | 31 | no |
| 7 | 36 | no |
| 8 | 41 | yes |
| 9 | 46 | no |
| 10 | 51 | no |
Questions
What is x in 5x + 1 = 41?
The solution of 5x + 1 = 41 is x = 8.
How do you solve 5x + 1 = 41?
Subtract 1 from both sides to get 5x = 40, then divide both sides by 5 to get x = 8.
How do I check the answer?
Replace x by 8: 5(8) + 1 = 41, which is 41.