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Solve 4x āˆ’ 4 = 32

The solution of 4x āˆ’ 4 = 32 is x = 9.

The lines y = 4x āˆ’ 4 and y = 32 meet at x = 9468101214102030405060x = 9y = 4x āˆ’ 4y = 32
The lines y = 4x āˆ’ 4 and y = 32 meet at x = 9. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    4xāˆ’4=324x - 4 = 32
  2. 2

    Add 4 to both sides:

    4xāˆ’4+4=32+4 ⇒ 4x=364x - 4 + 4 = 32 + 4 \ \Rightarrow\ 4x = 36
  3. 3

    Divide both sides by 4:

    4x4=364 ⇒ x=9\frac{4x}{4} = \frac{36}{4} \ \Rightarrow\ x = 9
  4. 4

    Check: put x = 9 back into the equation.

    4ā‹…9āˆ’4=36āˆ’4=32āœ“4\cdot9 - 4 = 36 - 4 = 32 \checkmark
LaTeX source of the formulas on this page
\[ 4x - 4 = 32\ \Rightarrow\ x = 9 \]
\[ 4x - 4 = 32 \]
\[ 4x - 4 + 4 = 32 + 4 \ \Rightarrow\ 4x = 36 \]
\[ \frac{4x}{4} = \frac{36}{4} \ \Rightarrow\ x = 9 \]
\[ 4\cdot9 - 4 = 36 - 4 = 32 \checkmark \]

Trying values of x in 4x āˆ’ 4 = 32

x4x āˆ’ 4Equals 32?
724no
828no
932yes
1036no
1140no

Questions

What is x in 4x āˆ’ 4 = 32?

The solution of 4x āˆ’ 4 = 32 is x = 9.

How do you solve 4x āˆ’ 4 = 32?

Add 4 to both sides to get 4x = 36, then divide both sides by 4 to get x = 9.

How do I check the answer?

Replace x by 9: 4(9) āˆ’ 4 = 32, which is 32.

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