Solve 5x − 4 = 41

The solution of 5x − 4 = 41 is x = 9.

5x - 4 = 41\ \Rightarrow\ x = 9

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The lines y = 5x − 4 and y = 41 meet at x = 9. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

1
The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.
$5x - 4 = 41$
2
Add 4 to both sides:
$5x - 4 + 4 = 41 + 4 \ \Rightarrow\ 5x = 45$
3
Divide both sides by 5:
$\frac{5x}{5} = \frac{45}{5} \ \Rightarrow\ x = 9$
4
Check: put x = 9 back into the equation.
$5\cdot9 - 4 = 45 - 4 = 41 \checkmark$

LaTeX source of the formulas on this page

\[ 5x - 4 = 41\ \Rightarrow\ x = 9 \]
\[ 5x - 4 = 41 \]
\[ 5x - 4 + 4 = 41 + 4 \ \Rightarrow\ 5x = 45 \]
\[ \frac{5x}{5} = \frac{45}{5} \ \Rightarrow\ x = 9 \]
\[ 5\cdot9 - 4 = 45 - 4 = 41 \checkmark \]

Trying values of x in 5x − 4 = 41

x	5x − 4	Equals 41?
7	31	no
8	36	no
9	41	yes
10	46	no
11	51	no

Questions

What is x in 5x − 4 = 41?

The solution of 5x − 4 = 41 is x = 9.

How do you solve 5x − 4 = 41?

Add 4 to both sides to get 5x = 45, then divide both sides by 5 to get x = 9.

How do I check the answer?

Replace x by 9: 5(9) − 4 = 41, which is 41.

Solve 5x − 4 = 41

How to work it out

Trying values of x in 5x − 4 = 41

Questions

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