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Solve 4x āˆ’ 15 = 45

The solution of 4x āˆ’ 15 = 45 is x = 15.

The lines y = 4x āˆ’ 15 and y = 45 meet at x = 15101214161820203040506070x = 15y = 4x āˆ’ 15y = 45
The lines y = 4x āˆ’ 15 and y = 45 meet at x = 15. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    4xāˆ’15=454x - 15 = 45
  2. 2

    Add 15 to both sides:

    4xāˆ’15+15=45+15 ⇒ 4x=604x - 15 + 15 = 45 + 15 \ \Rightarrow\ 4x = 60
  3. 3

    Divide both sides by 4:

    4x4=604 ⇒ x=15\frac{4x}{4} = \frac{60}{4} \ \Rightarrow\ x = 15
  4. 4

    Check: put x = 15 back into the equation.

    4ā‹…15āˆ’15=60āˆ’15=45āœ“4\cdot15 - 15 = 60 - 15 = 45 \checkmark
LaTeX source of the formulas on this page
\[ 4x - 15 = 45\ \Rightarrow\ x = 15 \]
\[ 4x - 15 = 45 \]
\[ 4x - 15 + 15 = 45 + 15 \ \Rightarrow\ 4x = 60 \]
\[ \frac{4x}{4} = \frac{60}{4} \ \Rightarrow\ x = 15 \]
\[ 4\cdot15 - 15 = 60 - 15 = 45 \checkmark \]

Trying values of x in 4x āˆ’ 15 = 45

x4x āˆ’ 15Equals 45?
1337no
1441no
1545yes
1649no
1753no

Questions

What is x in 4x āˆ’ 15 = 45?

The solution of 4x āˆ’ 15 = 45 is x = 15.

How do you solve 4x āˆ’ 15 = 45?

Add 15 to both sides to get 4x = 60, then divide both sides by 4 to get x = 15.

How do I check the answer?

Replace x by 15: 4(15) āˆ’ 15 = 45, which is 45.

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