Solve 4x − 15 = 41

The solution of 4x − 15 = 41 is x = 14.

4x - 15 = 41\ \Rightarrow\ x = 14

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The lines y = 4x − 15 and y = 41 meet at x = 14. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

1
The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.
$4x - 15 = 41$
2
Add 15 to both sides:
$4x - 15 + 15 = 41 + 15 \ \Rightarrow\ 4x = 56$
3
Divide both sides by 4:
$\frac{4x}{4} = \frac{56}{4} \ \Rightarrow\ x = 14$
4
Check: put x = 14 back into the equation.
$4\cdot14 - 15 = 56 - 15 = 41 \checkmark$

LaTeX source of the formulas on this page

\[ 4x - 15 = 41\ \Rightarrow\ x = 14 \]
\[ 4x - 15 = 41 \]
\[ 4x - 15 + 15 = 41 + 15 \ \Rightarrow\ 4x = 56 \]
\[ \frac{4x}{4} = \frac{56}{4} \ \Rightarrow\ x = 14 \]
\[ 4\cdot14 - 15 = 56 - 15 = 41 \checkmark \]

Trying values of x in 4x − 15 = 41

x	4x − 15	Equals 41?
12	33	no
13	37	no
14	41	yes
15	45	no
16	49	no

Questions

What is x in 4x − 15 = 41?

The solution of 4x − 15 = 41 is x = 14.

How do you solve 4x − 15 = 41?

Add 15 to both sides to get 4x = 56, then divide both sides by 4 to get x = 14.

How do I check the answer?

Replace x by 14: 4(14) − 15 = 41, which is 41.

Solve 4x − 15 = 41

How to work it out

Trying values of x in 4x − 15 = 41

Questions

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