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Solve 4x āˆ’ 12 = āˆ’52

The solution of 4x āˆ’ 12 = āˆ’52 is x = -10.

The lines y = 4x āˆ’ 12 and y = -52 meet at x = -10-16-14-12-10-8-6-4-80-70-60-50-40-30x = -10y = 4x āˆ’ 12y = -52
The lines y = 4x āˆ’ 12 and y = -52 meet at x = -10. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    4xāˆ’12=āˆ’524x - 12 = -52
  2. 2

    Add 12 to both sides:

    4xāˆ’12+12=āˆ’52+12 ⇒ 4x=āˆ’404x - 12 + 12 = -52 + 12 \ \Rightarrow\ 4x = -40
  3. 3

    Divide both sides by 4:

    4x4=āˆ’404 ⇒ x=āˆ’10\frac{4x}{4} = \frac{-40}{4} \ \Rightarrow\ x = -10
  4. 4

    Check: put x = -10 back into the equation.

    4ā‹…(āˆ’10)āˆ’12=āˆ’40āˆ’12=āˆ’52āœ“4\cdot(-10) - 12 = -40 - 12 = -52 \checkmark
LaTeX source of the formulas on this page
\[ 4x - 12 = -52\ \Rightarrow\ x = -10 \]
\[ 4x - 12 = -52 \]
\[ 4x - 12 + 12 = -52 + 12 \ \Rightarrow\ 4x = -40 \]
\[ \frac{4x}{4} = \frac{-40}{4} \ \Rightarrow\ x = -10 \]
\[ 4\cdot(-10) - 12 = -40 - 12 = -52 \checkmark \]

Trying values of x in 4x āˆ’ 12 = āˆ’52

x4x āˆ’ 12Equals -52?
-12-60no
-11-56no
-10-52yes
-9-48no
-8-44no

Questions

What is x in 4x āˆ’ 12 = āˆ’52?

The solution of 4x āˆ’ 12 = āˆ’52 is x = -10.

How do you solve 4x āˆ’ 12 = āˆ’52?

Add 12 to both sides to get 4x = -40, then divide both sides by 4 to get x = -10.

How do I check the answer?

Replace x by -10: 4(-10) āˆ’ 12 = -52, which is -52.

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    Solve 4x āˆ’ 12 = āˆ’52: x = -10 (steps and check) | WordGPT