Solve 3x + 8 = ā1
The solution of 3x + 8 = ā1 is x = -3.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 8 from both sides:
- 3
Divide both sides by 3:
- 4
Check: put x = -3 back into the equation.
LaTeX source of the formulas on this page
\[ 3x + 8 = -1\ \Rightarrow\ x = -3 \]
\[ 3x + 8 = -1 \]
\[ 3x + 8 - 8 = -1 - 8 \ \Rightarrow\ 3x = -9 \]
\[ \frac{3x}{3} = \frac{-9}{3} \ \Rightarrow\ x = -3 \]
\[ 3\cdot(-3) + 8 = -9 + 8 = -1 \checkmark \]Trying values of x in 3x + 8 = ā1
| x | 3x + 8 | Equals -1? |
|---|---|---|
| -5 | -7 | no |
| -4 | -4 | no |
| -3 | -1 | yes |
| -2 | 2 | no |
| -1 | 5 | no |
Questions
What is x in 3x + 8 = ā1?
The solution of 3x + 8 = ā1 is x = -3.
How do you solve 3x + 8 = ā1?
Subtract 8 from both sides to get 3x = -9, then divide both sides by 3 to get x = -3.
How do I check the answer?
Replace x by -3: 3(-3) + 8 = -1, which is -1.