Solve 4x + 8 = ā4
The solution of 4x + 8 = ā4 is x = -3.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 8 from both sides:
- 3
Divide both sides by 4:
- 4
Check: put x = -3 back into the equation.
LaTeX source of the formulas on this page
\[ 4x + 8 = -4\ \Rightarrow\ x = -3 \]
\[ 4x + 8 = -4 \]
\[ 4x + 8 - 8 = -4 - 8 \ \Rightarrow\ 4x = -12 \]
\[ \frac{4x}{4} = \frac{-12}{4} \ \Rightarrow\ x = -3 \]
\[ 4\cdot(-3) + 8 = -12 + 8 = -4 \checkmark \]Trying values of x in 4x + 8 = ā4
| x | 4x + 8 | Equals -4? |
|---|---|---|
| -5 | -12 | no |
| -4 | -8 | no |
| -3 | -4 | yes |
| -2 | 0 | no |
| -1 | 4 | no |
Questions
What is x in 4x + 8 = ā4?
The solution of 4x + 8 = ā4 is x = -3.
How do you solve 4x + 8 = ā4?
Subtract 8 from both sides to get 4x = -12, then divide both sides by 4 to get x = -3.
How do I check the answer?
Replace x by -3: 4(-3) + 8 = -4, which is -4.