Solve 3x + 4 = ā20
The solution of 3x + 4 = ā20 is x = -8.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 4 from both sides:
- 3
Divide both sides by 3:
- 4
Check: put x = -8 back into the equation.
LaTeX source of the formulas on this page
\[ 3x + 4 = -20\ \Rightarrow\ x = -8 \]
\[ 3x + 4 = -20 \]
\[ 3x + 4 - 4 = -20 - 4 \ \Rightarrow\ 3x = -24 \]
\[ \frac{3x}{3} = \frac{-24}{3} \ \Rightarrow\ x = -8 \]
\[ 3\cdot(-8) + 4 = -24 + 4 = -20 \checkmark \]Trying values of x in 3x + 4 = ā20
| x | 3x + 4 | Equals -20? |
|---|---|---|
| -10 | -26 | no |
| -9 | -23 | no |
| -8 | -20 | yes |
| -7 | -17 | no |
| -6 | -14 | no |
Questions
What is x in 3x + 4 = ā20?
The solution of 3x + 4 = ā20 is x = -8.
How do you solve 3x + 4 = ā20?
Subtract 4 from both sides to get 3x = -24, then divide both sides by 3 to get x = -8.
How do I check the answer?
Replace x by -8: 3(-8) + 4 = -20, which is -20.