Solve 3x + 10 = ā2
The solution of 3x + 10 = ā2 is x = -4.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 10 from both sides:
- 3
Divide both sides by 3:
- 4
Check: put x = -4 back into the equation.
LaTeX source of the formulas on this page
\[ 3x + 10 = -2\ \Rightarrow\ x = -4 \]
\[ 3x + 10 = -2 \]
\[ 3x + 10 - 10 = -2 - 10 \ \Rightarrow\ 3x = -12 \]
\[ \frac{3x}{3} = \frac{-12}{3} \ \Rightarrow\ x = -4 \]
\[ 3\cdot(-4) + 10 = -12 + 10 = -2 \checkmark \]Trying values of x in 3x + 10 = ā2
| x | 3x + 10 | Equals -2? |
|---|---|---|
| -6 | -8 | no |
| -5 | -5 | no |
| -4 | -2 | yes |
| -3 | 1 | no |
| -2 | 4 | no |
Questions
What is x in 3x + 10 = ā2?
The solution of 3x + 10 = ā2 is x = -4.
How do you solve 3x + 10 = ā2?
Subtract 10 from both sides to get 3x = -12, then divide both sides by 3 to get x = -4.
How do I check the answer?
Replace x by -4: 3(-4) + 10 = -2, which is -2.